Harder rIdDlE

Subject: Harder rIdDlE Fri May 08, 2009 9:37 am

A jeweler has ten groups of rings. Every group weighs 100 grams, it means that every ring weighs 10 grams. But only one group of the rings weighs only 90 gram that means that every ring weighs 9 grams. The question is how did the jeweler know the fake group by putting rings in the scale once?

Subject: Re: Harder rIdDlE Sat May 09, 2009 2:21 pm

I am going to try my luck this time

The jeweler took a ring of the first

group, two rings of the second one,

three rings of the third, 4 of the 4th, 5

of the 5th, 6 of the 6th, 7 of the 7th, 8

of the 8th, 9 of the 9th, and the whole

10th group and put them in the scale.
So, when he saw the total he knew the

fake group.{ It means that, if the

missing was one gram of the total,

the fake group would be the first

one. And if the missing were 2 grams

so, it's the second group. And so on}

Subject: Re: Harder rIdDlE Sat May 09, 2009 10:57 pm

As I think this is the correct answer, I believe that this riddle is not plotted sharply. I mean there is still a gap in this woven story. The gap is that the missing amount is not necessary to be hierarchically systematic. For instance, if the missing amount was 1 gram, there is no keen proof that the missing is in the first group. It is still logical to be in any other group, and so on.

I already heard this riddle from some one, and I offered my explanation above upon hearing the answer, and hope to hear other people's comments.

wishes,

Subject: Re: Harder rIdDlE Sun May 10, 2009 5:10 pm

Subject: Re: Harder rIdDlE Sun May 10, 2009 11:25 pm

Hello,
Are you waiting for me to answer??!! Actually, I myself don't know the answer of this puzzle. But I think what Passion said was right. Regarding the gap, there's no gap Admin!! Where is the gap??
We can put the ten groups next to each other then take one ring from the first group, two from the second one, etc then nine from the ninth one. If the missing weight is 1 gram, it would be the first one and if it is nine grams it would be the ninth group, etc. But in case there is no missing weight, it would be the tenth one.
I think this is the only solution.

Thank you

Subject: Re: Harder rIdDlE Sun May 10, 2009 11:55 pm

Thank you Heron..

But I am still not convinced ... IF the missing was 3 grams, what is the keen proof that this missing is in the third group? Maybe there is one ring that weights 3 grams less than the others, and other ring weights 5 grams less, and other ring weight 2 grams more than the others. So, we cannot confirm that the rings are all of the same weight and that the missing is systematic. Has my idea become clear?
Hope to read comments from all of you.

Subject: Re: Harder rIdDlE Mon May 11, 2009 12:31 am

Adminnn!!!!!

The text of the riddle says" every ring weighs 10 grams". I mean that is a rule in all the groups except one group " every ring weighs 9 grams".

I said after rings are collected:
The total weight should be 45 grams.
If it is 45 then the tenth group is the fake one.
If it is 44 then the first group is the fake one.
If it is 43 then the second group is the fake one.
If it is 42 then the third group is the fake one.
If it is 41 then the fourth group is the fake one.
If it is 40 then the fifth group is the fake one.
If it is 39 then the sixth group is the fake one.
If it is 38 then the seventh group is the fake one.
If it is 37 then the eighth group is the fake one.
If it is 36 then the ninth group is the fake one.